c - Buffer Overflow -

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i trying create buffer overflow. there 3 variables in function -- int, , 2 arrays. 2 arrays both length of 14 chars. int initialized 0 in function, trying change 1. run program terminal , put in input assign second array.

therefore, when run program, doing this: 

./a.out 11111111111111111111111111111

this 29 1's. overflows 2 arrays making them both 1's, , want put 29th "1" int, reason gets converted decimal number "49." how able put "1" int using buffer overflow without converting?

i not able put decimal version of 1 because unprintable character in ascii.

the ascii value of character 1 0x31, 49 in decimal. on right track.

what doing invokes undefined behavior anyway, expected behavior form of undefined behavior.

to try , change integer 1, can run

./a.out 1111111111111111111111111111^a

where ^a obtained pressing control , a keys, shell's line editor interpret command move cursor beginning of line... can try instead:

./a.out $(printf '1111111111111111111111111111\001')

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