r - Are all dates in order -

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i trying apply diff() on series of columns containing dates. interested in difference between date1-date2, date2-date3, etc.

i interested in:

  1. the actual difference between dates (days)
  2. if dates of row in order (diff >= 0, row)

i can use diff() on series of dates (e.g. on first row --> diff(unlist(df1[1,])) ). need apply per row, guess using apply(), reason can't work out. dates missing, allowed in study.

hopefully easy guys...

df <- structure(list(date1 = structure(c(-10871, -13634, -15937, -15937,  -290, -2323), class = "date"), date2 = structure(c(16678, na,16037, 16659,  16538, 16626), class = "date"), date3 = structure(c(16685,16688, na, 16659,  16568, 16672), class = "date"), date4 = structure(c(16701, 16695, 16670,  16661, 16582, 16672), class = "date"), date5 = structure(c(16709, 16695,  16661, 16667, 16619, 16692), class = "date")), .names = c("date1","date2",  "date3", "date4", "date5"), row.names = c("2", "3", "4", "5", "6", "7"),  class = "data.frame") df

you can try this:

apply(df, 1, function(x) identical(sort(as.date(x)), as.date(x[!is.na(x)])))

it providing output this, says whether particular rows dates in sorted order.

    2     3     4     5     6     7   true  true false  true  true  true

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