python - How to make a diagonal matrix with canopy that has a displacement in the diagonal? -

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i need create diagonal matrix diagonal displaced left or right center help?

as down-votes of question suggest, should try explain question in better way. being said, best guess you're looking superdiagonal , subdiagonal matrices; i.e.:

superdiagonal:

0 1 0 0 0 0 1 0 0 0 0 1 0 0 0 0

subdiagonal:

0 0 0 0 1 0 0 0 0 1 0 0 0 0 1 0

if that's case, can use numpy's indices:

import numpy np superdiagonal = np.zeros((4, 4)) i, j = np.indices(superdiagonal.shape) superdiagonal[i == j-1] = 1 print(superdiagonal)

this give you:

array([[ 0.,  1.,  0.,  0.],        [ 0.,  0.,  1.,  0.],        [ 0.,  0.,  0.,  1.],        [ 0.,  0.,  0.,  0.]])

for subdiagonal, have change i == j-1 part i == j+1.


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