Less mixin, extract colors from array and on hover, add darken to that array -

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is possible darken array colors? this:

@array: @color1 @color2 @color3 @color4 .color-mix(@i) when (@i > 0) {     .myclass {         li:nth-child(@{i}) {             .background-color(extract(@array, @i));             &:hover {               // not working, there right approach this?                 .background-color(extract(darken(@array, 5.5%, @i)));             }         }     .color-mix(@i - 1);     } } // iterate .color-mix(4);

if understand question correctly, yes, can achieve that. below how it. code correct except instead of trying darken extracted value, trying extract darkened value (which not possible).

@array: #fff #00f #ff0 #f00;  .color-mix(@i) when (@i > 0) {   .myclass {     li:nth-child(@{i}) {       .background-color(extract(@array, @i));       &:hover {         .background-color(darken(extract(@array, @i), 5.5%));       }     }   }     .color-mix(@i - 1); /* have moved because think wrongly placed */ } // iterate .color-mix(4);

one improvement suggest code move :hover selector within .background-color mixin below. makes bit more easier read there no wrapping of function call within function , on.

@array: #fff #00f #ff0 #f00;  .color-mix(@i) when (@i > 0) {   .myclass {     li:nth-child(@{i}) {       .background-color(extract(@array, @i));     }   }     .color-mix(@i - 1); } // iterate .color-mix(4);  .background-color(@color){   &{     background-color: @color;     &:hover{       background-color: darken(@color, 5.5%);     }   } }

even better - avoid mixin if can :)

@array: #fff #00f #ff0 #f00;  .color-mix(@i) when (@i > 0) {   .myclass {     li:nth-child(@{i}) {       @color: extract(@array, @i);       background-color: @color;       &:hover{         background-color: darken(@color, 5.5%);       }     }   }     .color-mix(@i - 1); } // iterate .color-mix(4);

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