how to display images from folder while displaying image by name using php? -
i have 2 folders, 1)- 23feb2016
, 2)- 23feb2016
. want 1 image folder1
, 1 folder2
, image name must unique, userid
etc.
this html code:
<div class="col-md-12"> <div class="col-md-6"> <image src="../images/registered/20115.jpg" style="width: 100%; height: 100%"></image> registered </div> <div class="col-md-6"> <image src="../images/registered/20115.jpg" style="width: 100%; height: 100%"></image> attendance </div> </div>
you can use following approach find unique files.
//path directory scan $directory1 = "./folder1/"; $directory2 = "./folder2/"; //get image files .jpg extension. $jpgfolder1 = glob($directory1 . "*.jpg"); $jpgfolder2 = glob($directory2 . "*.jpg"); $uniqeimage[]; if(($jpgfolder1 != null) && ($jpgfolder2 != null)) { $uniqeimage = array_unique(array_intersect($jpgfolder1, $jpgfolder2)); }
now array variable $uniqeimage[] contains unique file names using can construct html
foreach($uniqeimage $img) { echo("<div class='col-md-12'>"); echo(" <div class='col-md-6'>"); echo(" <image src='../images/folder1/" . $img . ".jpg' style='width: 100%; height: 100%'></image> registered"); echo(" </div>"); echo(" <div class='col-md-6'>"); echo(" <image src='../images/folder2/" . $img . ".jpg' style='width: 100%; height: 100%'></image> attendance"); echo(" </div>"); echo("</div>"); }
Comments
Post a Comment