PHP How to access argument of function inside anonymous function? -

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i need access first argument function inside anonymous function passed second argument said function. example:

<?php function a($arg, $func) {     echo $func(); } a("argument 1", function () use($arg) {return $arg;}); ?>

the above return following error:

notice: undefined variable: arg in path/to/file.php on line 5

while desired result be:

argument 1

try below solution:

function a($arg, $func) {     echo $func($arg); } a("argument 1", function ($arg) {return $arg;});

output

argument 1

for more detail have @ http://php.net/manual/en/functions.anonymous.php


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